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Home/ Questions/Q 696231
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T03:02:31+00:00 2026-05-14T03:02:31+00:00

I´m building a jquery animation from a multidimensional array, and in the callback of

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I´m building a jquery animation from a multidimensional array, and in the callback of each iteration i would like to use an element of the array. However somehow I always end up with last element of the array instead of all different elements.

html:

<div id="square" style="background-color: #33ff33; width: 100px; height: 100px; position: absolute; left: 100px;"></div>

javascript:

$(document).ready(function () {

// Array with Label, Left pixels and Animation Lenght (ms)
LoopArr = new Array(
    new Array(['Dog', 50, 500]),
    new Array(['Cat', 150, 5000]),
    new Array(['Cow', 200, 1500])
);

$('#square').click(function() {

for (x in LoopArr) {
    $("#square").animate({ left: LoopArr[x][0][1] }, LoopArr[x][0][2], function() {
        alert (LoopArr[x][0][0]);
    });
}

});

});

`

Current result: Cow, Cow, Cow

Desired result: Dog, Cat, Cow

How can I make sure the relevant array element is returned in the callback?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T03:02:31+00:00Added an answer on May 14, 2026 at 3:02 am

    The problem is that x is modified by the time the callback evaluates it. You need to create a separate closure for it:

    for (x in LoopArr) {
        $("#square").animate({ left: LoopArr[x][0][1] }, LoopArr[x][0][2], 
          (function (z) {
            return function() {
                alert (LoopArr[z][0][0]);
            }
        })(x));
    }
    

    I’ve renamed the parameter to z here for clarification, you’re passing x as an argument to the function, which returns a function that makes use of the scoped z variable, which stores the state of x when it is passed.

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