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Home/ Questions/Q 280665
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T05:08:16+00:00 2026-05-12T05:08:16+00:00

I’m building a per-user file browsing/uploading application using Django and when I run this

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I’m building a per-user file browsing/uploading application using Django and when I run this function


def walkdeep(request, path):
    path, dirs, files = walktoo('/home/damon/walktemp/%s' % path)
    return render_to_response('walk.html', {
        'path' : path[0],
        'dirs' : path[1],
        'files' : path[2],
    }, context_instance=RequestContext(request))

def walktoo(dir):
    for path, dirs, files in os.walk(dir):
        yield path, dirs, files
    print path, dirs, files

I get this error:

need more than 1 value to unpack

Also, i know this is a silly way to do this, any advice would be appreciated.

edit:

this was actually very silly on my part, i completely forgot about os.listdir(dir) which is a much more reasonable function for my purposes. if you use the selected answer, it clears up the above issue i was having, but not with the results i wanted.

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  1. Editorial Team
    Editorial Team
    2026-05-12T05:08:17+00:00Added an answer on May 12, 2026 at 5:08 am
    path, dirs, files = walktoo('/home/damon/walktemp/%s' % path)
    

    In this line, you’re expecting walktoo to return a tuple of three values, which are then to be unpacked into path, dirs, and files. However, your walktoo function is a generator object: calling walktoo() yields a single value, the generator. You have to call next() on the generator (or call it implicitly by doing some sort of iteration on it) to get what you actually want, namely the 3-tuple that it yields.

    I’m not entirely clear what you want to do — your walkdeep() function is written like it only wants to use the first value returned by walktoo(). Did you mean to do something like this?

    for path, dirs, files in walktoo(...):
        # do something
    
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