Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6540111
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T10:56:20+00:00 2026-05-25T10:56:20+00:00

I’m building a Python script to do a network inventory on our internal system.

  • 0

I’m building a Python script to do a network inventory on our internal system. Each system has up to five clusters and I am looking for a way to adjust the list to put them all into one line per cluster. Here’s the way they are stored on the system:

Cluster One
Primary System
Node One
x.x.x.x (Node IP)
Node two
x.x.x.x (Node IP)
Cluster Two
Primary System
Node One
x.x.x.x (Node IP)
Node two
x.x.x.x (Node IP)

I need to have them adjusted to look like this:

Cluster One,Primary System,Node One,x.x.x.x (Node IP),Node Two,x.x.x.x (Node IP)
Cluster Two,Primary System,Node One,x.x.x.x (Node IP),Node Two,x.x.x.x (Node IP)

Here is some REALLY sloppy code I’m using right now, but I was wondering if there is a more efficient way to do it:

NetworkTableCount = len(NetworkTable) / 6 + 1
    count = 1
    while count < NetworkTableCount:
            if count == 1:
                    Temp = (NetworkTable[0]+","+NetworkTable[1]+","+NetworkTable[2]+","+NetworkTable[3]+","+NetworkTable[4]+","+NetworkTable[5]+"\n")
            elif count == 2:
                    Temp = (NetworkTable[6]+","+NetworkTable[7]+","+NetworkTable[8]+","+NetworkTable[9]+","+NetworkTable[10]+","+NetworkTable[11]+"\n")
            elif count == 3:
                    Temp = (NetworkTable[12]+","+NetworkTable[13]+","+NetworkTable[14]+","+NetworkTable[15]+","+NetworkTable[16]+","+NetworkTable[17]+"\n")
            elif count == 4:
                    Temp = (NetworkTable[18]+","+NetworkTable[19]+","+NetworkTable[20]+","+NetworkTable[21]+","+NetworkTable[22]+","+NetworkTable[23]+"\n")
            elif count == 5:
                    Temp = (NetworkTable[24]+","+NetworkTable[25]+","+NetworkTable[26]+","+NetworkTable[27]+","+NetworkTable[28]+","+NetworkTable[29]+"\n")
            NetworkTopology.write(Temp)
            count = count + 1

I’m self taught in Python so it may just be a simple adjustment. Thanks in advance.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T10:56:21+00:00Added an answer on May 25, 2026 at 10:56 am

    First look: How do you split a list into evenly sized chunks?

    Using one of the answers:

    >>> import itertools
    >>> NetworkTable
    ['Cluster One', 'Primary System', 'Node One', 'x.x.x.x (Node IP)', 'Node two', 'x.x.x.x (Node IP)', 'Cluster Two', 'Primary System', 'Node One', 'x.x.x.x (Node IP)', 'Node two', 'x.x.x.x (Node IP)']
    >>> l = [NetworkTable[i:i+6] for i in range(0, len(NetworkTable), 6)]
    >>> l
    [['Cluster One', 'Primary System', 'Node One', 'x.x.x.x (Node IP)', 'Node two', 'x.x.x.x (Node IP)'], ['Cluster Two', 'Primary System', 'Node One', 'x.x.x.x (Node IP)', 'Node two', 'x.x.x.x (Node IP)']]
    >>> #Now it's easy. Do what you want with l.
    >>> [", ".join(i) + "\n" for i in l]
    ['Cluster One, Primary System, Node One, x.x.x.x (Node IP), Node two, x.x.x.x (Node IP)\n', 'Cluster Two, Primary System, Node One, x.x.x.x (Node IP), Node two, x.x.x.x (Node IP)\n']
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Basically, what I'm trying to create is a page of div tags, each has
We're building an app, our first using Rails 3, and we're having to build
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I want to count how many characters a certain string has in PHP, but
I have a jquery bug and I've been looking for hours now, I can't
I've got a string that has curly quotes in it. I'd like to replace
We are using XSLT to translate a RIXML file to XML. Our RIXML contains
I have just tried to save a simple *.rtf file with some websites and

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.