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Editorial Team
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Asked: 2026-06-18T16:12:18+00:00

I’m building a simple email program. I use this to get the HTML: $bodyHTML

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I’m building a simple email program.

I use this to get the HTML: $bodyHTML = imap_fetchbody($imap, $i, 2);

When I use: $bodyHTML = imap_fetchbody($imap, $i, 1.2); the output is empty…

When I echo the $bodyHTML. I see this:

=EF=BB=BF<!DOCTYPE HTML PUBLIC =22-//W3C//DTD HTML 4.0 Transitional//EN=22>
<HTML><HEAD><TITLE>Country Linedance Just Can't See It www.country4all.eu</=
TITLE>
<META name=3DGENERATOR content=3D=22MSHTML 8.00.6001.19019=22>
<STYLE>A:hover {
=09BACKGROUND-COLOR: yellow; COLOR: rgb(0,0,153)
}
</STYLE>

Now my question is: how can I set this correctly to HTML? (So it shows in the browser)

UPDATE:
I found that this is a common problem. People advice $bodyHTML = imap_fetchbody($imap, $i, 1.2); but most of the times this doesn’t work. So people use this:
1) $bodyHTML = imap_fetchbody($imap, $i, 2);
2) quoted_printable_decode($bodyHTML)

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1 Answer

  1. Editorial Team

    You can use the quoted_printable_decode method to decode the encoded special characters (like =22) to regular characters.

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