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Home/ Questions/Q 6246547
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:42:40+00:00 2026-05-24T12:42:40+00:00

I’m building a simple news aggregator with Ruby. I am completely new to the

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I’m building a simple news aggregator with Ruby. I am completely new to the language, and I just found out how to use the open uri function.

Now, my problem is how to parse the html page. Is there a built in parser in Ruby.

btw, I do not use rails and I want it to be very simple

Thanks in advance!

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:42:41+00:00Added an answer on May 24, 2026 at 12:42 pm

    The simple answer is yes, there’s a parser. I can’t answer your question specifically without knowing what you’re trying to extract from the html but I’ve included some source code below. If your able to read ruby code, then it’s pretty self explanatory.

    require 'open-uri'
    require 'pp'
    open('http://ruby-lang.org') do |f|
    puts "URI: #{f.base_uri}"
    puts "Content-type: #{f.content_type}, charset: #{f.charset}"
    puts "Encoding: #{f.content_encoding}"
    puts "Last modified: #{f.last_modified}"
    puts "Status: #{f.status.inspect}"
    pp f.meta
    puts "----"
    3.times {|i| puts "#{i}: #{f.gets}" }
    end
    

    produces:

    URI: http://www.ruby-lang.org/en/
    Content-type: text/html, charset: utf-8
    Encoding: []
    Last modified:
    Status: ["200", "OK"]
    {"date"=>"Mon, 15 Nov 2010 17:54:07 GMT",
    "server"=>
    "Apache/2.2.3 (Debian) DAV/2 SVN/1.4.2 mod_ruby/1.2.6 Ruby/1.8.5(2006-08-25)",
    "transfer-encoding"=>"chunked",
    "content-type"=>"text/html;charset=utf-8"}
    ----
    0: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN"
    1: "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
    2: <html xmlns="http://www.w3.org/1999/xhtml">
    

    Here’s another link showing an example of how to use open-uri: http://juretta.com/log/2006/08/13/ruby_net_http_and_open-uri/

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