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Home/ Questions/Q 6878193
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:41:36+00:00 2026-05-27T04:41:36+00:00

I’m building a StackOverflow mini-clone. I have the following database relations: questions – question_id

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I’m building a StackOverflow mini-clone. I have the following database relations:

questions 
- question_id
- title

tags
- tag_id
- name

question_tags
- foreign key tag_id
- foreign key question_id

Supposedly, this is the proper way to organize a tagging system.

Now, how could I query all questions with the tag ‘java’, and at the same time, when listing those questions, also show all the tags that each question is associated with?

I feel like denormalizing and putting an extra field into questions, say tag_string, which would have a listing of tags as CSV, so I can have a simpler query for this case.

Of course, it is not a problem when showing a single question:

  SELECT * FROM questions LEFT OUTER JOIN question_tags USING(question_id)
                          LEFT OUTER JOIN tags USING(tag_id)
                          WHERE question_id = 42;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:41:37+00:00Added an answer on May 27, 2026 at 4:41 am

    Ended up with a solution that looks like this:

        result = g.db.query(u" SELECT q.*, u.fullname, u.reputation, t2.tag_id, t2.name as tag_name, a.answer_id, qv.vote_id, qv.value as vote_value \
                           FROM tags t \
                           JOIN question_tags USING(tag_id) \
                           JOIN questions q USING(question_id) \
                           JOIN users u ON(q.author_id = u.user_id) \
                           JOIN question_tags qt2 ON(qt2.question_id = q.question_id) \
                           JOIN tags t2 ON(t2.tag_id = qt2.tag_id) \
                           LEFT OUTER JOIN answers a ON (a.question_id = q.question_id) \
                           LEFT OUTER JOIN question_votes qv ON (qv.question_id = q.question_id) \
                           WHERE (t.name = %s);", name)
    

    Somehow I was missing the fact that it is possible to join twice on the same table – first for matching tags and later for all tags for each question.

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