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Home/ Questions/Q 6956931
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:56:01+00:00 2026-05-27T14:56:01+00:00

I’m calculating the difference between 2 dates for which there are many differing examples

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I’m calculating the difference between 2 dates for which there are many differing examples available. The time returned is in milliseconds so I need to convert it into something more useful.

Most examples are for days:hours:minutes:seconds or hours:minutes, but I need days:hours:minutes so the seconds should be rounded up into the minutes.

The method I’m currently using gets close but shows 3 days as 2.23.60 when it should show 3.00.00 so something is not quite right. As I just grabbed the current code from an example on the web, I’m open to suggestions for other ways of doing this.

I’m obtaining the time in milliseconds by subtracting a start date from an end date as follows:-

date1 = new Date(startDateTime);
date2 = new Date(endDateTime);
ms = Math.abs(date1 - date2)

I basically need to take the ms variable and turn in into days.hours:minutes.

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:56:01+00:00Added an answer on May 27, 2026 at 2:56 pm

    Something like this?

    function dhm(t){
        var cd = 24 * 60 * 60 * 1000,
            ch = 60 * 60 * 1000,
            d = Math.floor(t / cd),
            h = Math.floor( (t - d * cd) / ch),
            m = Math.round( (t - d * cd - h * ch) / 60000),
            pad = function(n){ return n < 10 ? '0' + n : n; };
      if( m === 60 ){
        h++;
        m = 0;
      }
      if( h === 24 ){
        d++;
        h = 0;
      }
      return [d, pad(h), pad(m)].join(':');
    }
    
    console.log( dhm( 3 * 24 * 60 * 60 * 1000 ) );
    
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