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Home/ Questions/Q 8843145
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:08:45+00:00 2026-06-14T11:08:45+00:00

I’m calling a method in a for-loop that calls a method on a COM

  • 0

I’m calling a method in a for-loop that calls a method on a COM object (Inventor 2012).

The code used to be:

foreach (var occ in occurrences)
{
    // [...]
    SomeMethod(occ);
    // [...]

When refactoring I decided to inline the method call:

foreach (var occ in occurrences)
{
    // [...]
    BOMQuantityTypeEnum quantityType;
    object quantity;
    occ.Definition.BOMQuantity.GetBaseQuantity(out quantityType, out quantity);
    if (quantityType ==
    // [...]
}

While changing nothing else, this started failing, throwing E_INVALIDARG. Furthermore, it only fails the second time the method is called. However, by changing it to the following it works again:

    BOMQuantityTypeEnum quantityType = 0;
    object quantity = null;
    occ.Definition.BOMQuantity.GetBaseQuantity(out quantityType, out quantity);

Why would this happen?

Edit:

Could it be that the COM-object reads the value of the previous iteration?

The signature is given in the documentation (in VB) as:

Sub GetBaseQuantity(ByRef QuantityType As BOMQuantityTypeEnum, ByRef Quantity As [optional] VARIANT)

Is the C#-signature wrong? Aren’t COM-interfaces auto-generated?

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:08:46+00:00Added an answer on June 14, 2026 at 11:08 am

    Could it be that the COM-object reads the value of the previous iteration?

    Yes it does. There’s no equivalent of out in COM automation, other than for the return value of a method. How you ended up with out instead of ref is fairly mysterious. Probably just a bug in the IDL that was used to declare the COM interface. The only COM automation compatible IDL attributes are [in], [in,out] and [out,retval].

    Still shouldn’t be a problem, the COM server could just call VariantClear() to reset the variant. Seems it doesn’t want to do that either. You can’t fix that code, resetting the value yourself is certainly a good enough workaround.

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