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Home/ Questions/Q 4270680
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Editorial Team
  • 0
Editorial Team
Asked: May 21, 20262026-05-21T07:20:21+00:00 2026-05-21T07:20:21+00:00

I’m choosing between the following 2 designs. Which would you recommend and why? I’m

  • 0

I’m choosing between the following 2 designs. Which would you recommend and why?

I’m quite doubtful about placing get/set methods in interfaces in the second method. Any comments about this?

public class Foo {
    Time time;
    boolean hasTime();
    Time getTime() { return time; }
    void setTime() { this.time = time; }
}

public class Bar extends Foo {
    boolean hasTime() { return true; }
}

public class Baz extends Foo {
    boolean hasTime() { return false; }
}


main() {
    for (Foo foo : foos) {
        if (foo.hasTime()) {
            // do something
        }
    }
}

vs

public class Foo {
}

public class Bar extends Foo implements TimedObject {
    Time time;
    Time getTime() { return time; }
    void setTime() { this.time = time; }
}

public interface TimedObject {
    Time getTime();
    void setTime();
}

main() {
    for (Foo foo : foos) {
        if (foo instance of TimedObject) {
            // do something
        }
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-21T07:20:22+00:00Added an answer on May 21, 2026 at 7:20 am

    The second approach is definitely the better.

    In the first approach, the getters and setters exist in both Bar and Baz classes, and can be called … irrespective of what hasTime() returns!

    You could override the getter and setter in Baz so that they threw (for instance) an OperationNotSupported exception. But even that’s a bit “icky”:

    • If you compare how a program would use the two versions, the first one requires you to remember to call hasTime(), whereas with the second one the compiler will tell you if you forget to typecast to a type that is assignment compatible with TimedObject.

    • The first version violates the substitutability principle because Baz would behave in a way that is incompatible with its superclass Foo.

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