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Home/ Questions/Q 8961705
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T15:57:21+00:00 2026-06-15T15:57:21+00:00

I’m clustering the rows of an NxM matrix using kmeans . clustIdx = kmeans(data,

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I’m clustering the rows of an NxM matrix using kmeans.

clustIdx = kmeans(data, N_CLUST, 'EmptyAction', 'drop');

I then re-arrange the rows of my matrix to such that adjacent rows are in the same cluster

dataClustered = data(clustIdx,:);

However every time I run the cluster analysis I get more or less the same clusters but with different identities. Thus the structure in dataClustered looks the same after each iteration but the groups are in different orders.

I’d like to re-arrange my cluster identities such that the the lower cluster identities represent dense clusters and the higher numbers are the sparse clusters.

Is there a easy and/or intuitive way to do this?

ie. Convert

clustIdx = [1 2 3 2 3 2 4 4 4 4];

to

clustIdx = [4 2 3 2 3 2 1 1 1 1]

The identities themselves are arbitrary the information is contained in the grouping.

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  1. Editorial Team
    Editorial Team
    2026-06-15T15:57:22+00:00Added an answer on June 15, 2026 at 3:57 pm

    If I understand correctly, you want to assign cluster label 1 to the cluster with most points, cluster label 2 to the cluster with the second most points, etc.

    Assume you have a cluster label array called idx

    >> idx = [1 1 2 2 2 2 3 3 3]';
    

    Now you can relabel idx like this:

    %# count the number of occurrences
    cts = hist(idx,1:max(idx));
    
    %# sort the counts - now we know that 1 should be last
    [~,sortIdx] = sort(cts,'descend')
    sortIdx =
         2     3     1
    
    %# create a mapping vector (thanks @angainor)
    map(sortIdx) = 1:length(sortIdx);
    map =
         3     1     2
    
    %# and remap indices
    map(idx)
    ans =
         3     3     1     1     1     1     2     2     2
    
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