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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:40:59+00:00 2026-05-15T23:40:59+00:00

I’m coding a task monitoring, which updates tasks’ progress using cout. I’d like to

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I’m coding a task monitoring, which updates tasks’ progress using cout. I’d like to display one task progress per line, therefore I have to rollback several lines of the console.

I insist on “several” because \b does the job for one line, but does not erase \n between lines.

I tried std::cout.seekp(std::cout.tellp() - str.length()); but tellp() returns -1 (failure).

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  1. Editorial Team
    Editorial Team
    2026-05-15T23:41:00+00:00Added an answer on May 15, 2026 at 11:41 pm

    You can do cout << '\r'; to jump to the beginning of the current line, but moving upwards is system-specific. For Unix, see man termcap and man terminfo (and search for cursor_up). On ANSI-compatible terminals (such as most modern terminals available on Unix), this works to move up: cout << "\e[A";.

    Don’t try seeking in cout, it’s unseekable most of the time (except when redirected to a file).

    As mentioned in other answers, using the ncurses (or slang) library provides a good abstraction for terminal I/O on Unix.

    Instead of filling with spaces (which is error-prone, because not every terminal is 80 characters wide), you can do \r + clr_eol: std::cout << "\r\e[K" << std::flush.

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