Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 502877
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T06:20:11+00:00 2026-05-13T06:20:11+00:00

I’m coming from .NET world, and unfortunately looking Java source with .NET ‘s eyes.

  • 0

I’m coming from .NET world, and unfortunately looking Java source with .NET‘s eyes.

Following code is from Android Apps (though not Android specific at all):

    private class Worker implements Runnable {
        private final Object mLock = new Object();
        private Looper mLooper;

        Worker(String name) {
            Thread t = new Thread(null, this, name);
            t.start();
            synchronized (mLock) {
                while (mLooper == null) {
                    try {
                        mLock.wait();
                    } catch (InterruptedException ex) {
                    }
                }
            }
        }

        public Looper getLooper() {
            return mLooper;
        }

        public void run() {
            synchronized (mLock) {
                Looper.prepare();
                mLooper = Looper.myLooper();
                mLock.notifyAll();
            }
            Looper.loop();
        }

        public void quit() {
            mLooper.quit();
        }
    }

I’m not precisely clear with how synchronized works.
First I thought that synchronized is locking mLock object, but then if after t.start() constructor thread enters sync block first, it would block it at mLock.wait(), and implicitly block thread “t” by blocking it from entering synchronized block.

This is obviously wrong, because my phone rings as supposed 🙂

Next thought is that synchronize synchronizes “code block” (in which case, there two synchronized block are independent => threads can enter two different sync block at same time without restriction), and that fitted perfectly…

… until my colleague told me that mLock.wait() releases lock on mLock and enables other thread to enter critical section on mLock in same time.

I’m not sure if I was clear enough, so will gladly answer any further questions on this.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T06:20:11+00:00Added an answer on May 13, 2026 at 6:20 am

    Check out the javadoc on Object.wait(). It’s “magic” in that it drops the monitor that was acquired when entering the synchronized {} block. That allows another thread to acquire the monitor and call Object.notify().

    When another thread calls notify() to wake the waiting thread from its wait() call, the waiting thread must re-acquire the monitor and will block until it can — the monitor is only dropped for the duration of the wait() call. And the notifying thread completes its synchronized block before the newly-awoken waiting thread can proceed. Everything is sequenced predictably.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 408k
  • Answers 408k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer See: How to start a background process in Python? May 15, 2026 at 6:43 am
  • Editorial Team
    Editorial Team added an answer Here's one that works: module irc2; import std.stdio; class TestClass… May 15, 2026 at 6:43 am
  • Editorial Team
    Editorial Team added an answer Take a look at http://molvis.sdsc.edu/visres/molvisfw/titles.jsp for an amazing number of… May 15, 2026 at 6:43 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.