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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T16:43:30+00:00 2026-05-17T16:43:30+00:00

I’m compiling a lookup table that needs to have 133,784,560 entries, with values ranging

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I’m compiling a lookup table that needs to have 133,784,560 entries, with values ranging from 0 - 7,462

The maximum value of 7,462 can be contained within 13 bits. This gives us a lookup table of around 207 MB.

A 16 bit value increases our lookup table size around 50mb more.

The extra increase in size of the lookup table is not significant in todays age, but it would be nice to keep it as thin as possible.

When the LUT is loaded into memory, how much overhead is there to evaluate the value of a range of 13 bits, compared to evaluating the 16 bits? I’m assuming there would be some intermediary bitwise operations to convert it to a computer workable format, or am I wrong?

Every clock cycle counts, as this will be involved in a brute force analysis program that will run billions of comparisons. Should I just stick with the slightly larger LUT?

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  1. Editorial Team
    Editorial Team
    2026-05-17T16:43:30+00:00Added an answer on May 17, 2026 at 4:43 pm

    My guess would be that is a case of premature optimisation. Bit-fiddling is quite expensive, and will probably dwarf the extra memory-access cost, unless by sheer coincidence your cache performance hits an elbow somewhere between those two sizes.

    Ultimately, there’s no substitute for just trying it out.

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