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Home/ Questions/Q 8398309
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T21:01:13+00:00 2026-06-09T21:01:13+00:00

I’m confused as to why this works: Action myAction1 = () => myIntFunc(); …

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I’m confused as to why this works:

Action myAction1 = () => myIntFunc(); 
...
private Int32 myIntFunc() {
    return(4);
    }

I would expect the compiler to not allow this because an Action represents functions that do not return parameters, yet myIntFunc clearly returns a parameter.

As further evidence, note that this does not work:

Action myAction2 = myIntFunc;

So it’s like the lambda syntax is letting me get away with something I shouldn’t be able to get away with. I’m guessing I’m overlooking something to do with how Actions and lambdas work together…??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T21:01:15+00:00Added an answer on June 9, 2026 at 9:01 pm

    In the C# language specification, paragraph 6.5, one of the bullets says: If D has a void return type and the body of F is an expression, when each parameter of F is given the type of the corresponding parameter in D, the body of F is a valid expression (wrt §7) that would be permitted as a statement-expression (§8.6).

    So it’s OK to throw away the return value in that case.

    For a method group conversion, see paragraph 6.6 instead. Then the method must be compatible including the return type.

    So there’s a difference between anonymous method (lambda) and normal (named) method (or method group).

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