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Home/ Questions/Q 8874137
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T18:38:37+00:00 2026-06-14T18:38:37+00:00

I’m converting a CSV file to a local 2D array. I wanted to know

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I’m converting a CSV file to a local 2D array. I wanted to know if there is a better way to convert strings to floats/int rather then using regex followed by a parseFloat() / parseInt.

Ideas / Suggestions?

// numex() - checkes to see if the string (str) is a number
// returns number.valid (true||false) and number.value = (float||int||string)
numex = function(str){
  number = {};
  number.valid = false;
  number.value = str;
  // if we see a number then convert it to a floating point or integer
  if((number.value.search(/[^0-9^\.^\$^\%^\-^\"^,^ ]+/) < 0) && str.length > 0) {  
    number.valid = true;
    number.value = str.replace(/[^\-^0-9^\.]+/g, ''); // TODO add % coversion code for example if we see a 10% covert it to .1
    if(number.value.search(/[\.]/) >= 0) {  
       number.value = parseFloat(number.value); // replace floating point
    } else {
       number.value = parseInt(number.value); // replace integers
    }
  }
  return number; // number.valid = true or false;
}

var num = numex("1.101");
alert(num.value);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T18:38:38+00:00Added an answer on June 14, 2026 at 6:38 pm

    I don’t think you need to use regexp at all. Try this:

    var num = {};  
    num.value = new Number(str);  
    num.valid = !isNaN(num.value);
    

    Number constructor is more strict than parseInt and parseFloat in that it does not accept strings like 10aaa or 1.2bbb so there is no need to perform a regexp check.

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