Question

I’m creating a table of an arrays where the user can input the value themselves, and I will show them the table of value except the number 0 is use to exit from the scanf

so I don’t want number 0 to be store in the array

but I’m seeing number 0 for the next value of an array so I’m wondering if 0 is a default value of an array.

to make it a bit more clear

let say the user entered;

5
4
3
2

1

and 0

so what I suppose to show in my program output is

5
4
3
2
1

which I use array to display the index of 0-4 [1-5]

but just to make sure if number 0 is not store so I call array[5] to see if the next value is 0 or something else and it always display 0 so I want to know if there is a way to make sure that 0 is not going to store in the array

this is what I use to make sure

if(enter != 0){

array[i - 1] = enter;

Sorry if my question is complicated.

Thanks

Answer 1

I revide my answer. Every array that you allocate can contain garbage, or not. The compiler can clear it for you, or not. In your case, I would clear the array with something like -1. Else you will have some undefined values in there, that be 0 or not. It’s just not defined, every compiler can behave differently.

Test it:

#include <stdio.h>


void array(void);

int main(void) {
    int c[10], i;
    printf("Array 1: ");
    for(i = 0; i < 10; i++) {
        printf("%d", c[i]);
    }

    printf("\n");
    array();
    int b[10];
    for(i = 0; i < 10; i++) {
        printf("%d ",b[i]);
    }

    printf("\n");

    return 0;
}

void array(void) {
    int a[10] = {1,2,3,4,5,6,7,8,9,0};
    return;
}