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Home/ Questions/Q 6250799
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:29:42+00:00 2026-05-24T13:29:42+00:00

I’m creating ten buttons and the button texts are labelled 1 to 10. The

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I’m creating ten buttons and the button texts are labelled 1 to 10. The following code creates 10 buttons and labels correctly. But it’s printing 9 as the output for all the buttons. What I expect it to do is to print the corresponding number of the Button to screen, So for Example if the user presses Button 2 then it should print 2.

def create():
for i in range (1,10):
    lst.insert(i,Button(text=i,command=lambda: prnt(i)).pack())

(Note: ‘prnt(i)’ is a function that simply prints the value i has.
‘lst’ is a list that stores the created buttons.)

From the output I can say that the program is using the latest i value as the argument for the function when user presses a button, So how would I solve this without having to write 10 lines of code for each buttons.

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:29:44+00:00Added an answer on May 24, 2026 at 1:29 pm

    Try this (note the named argument to the lambda):

    def create():
        for i in range (1,10):
            lst.insert(i,Button(text=i,command=lambda i=i : prnt(i)).pack())
    

    This passes the value of i to the lambda as a local variable. Without this, you are using a reference to the original variable which will, of course, always resolve to whatever is stored in the original variable.

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