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Home/ Questions/Q 752285
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T14:45:50+00:00 2026-05-14T14:45:50+00:00

I’m curious how to specify options to a jQuery plugin in a way that

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I’m curious how to specify options to a jQuery plugin in a way that some are required, some are optionally overridden, and some can’t be touched.

I started off with the usual:

jQuery.fn.plugin = function (options){
  var defaults = { username: "", posts:10, api: "http://myapi.com" }
  var settings = jQuery.extend({}, defaults, options);
}

Let’s say I want username to be required, posts is optional (defaults to 10) and you (you being the user of the plugin) can’t change api, even if they try. Ideally, they’d all still be in the same data structure instead of being split into separate objects. Ideas?

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  1. Editorial Team
    Editorial Team
    2026-05-14T14:45:51+00:00Added an answer on May 14, 2026 at 2:45 pm

    If you wanted username to be required, I’d make it a parameter, given it’s the only required thing and there aren’t 20 parameters you want to do this way. Something like this:

    jQuery.fn.plugin = function (username, options){
      var defaults = { posts:10, api: "http://myapi.com" }
      var settings = jQuery.extend({}, defaults, options);
    }
    

    There’s not a clean required way to do this completely in a single passed object, at least not a simple one, which is what you want for an API. The alternative would be to specify no default and alert or something if it’s not there I suppose:

    jQuery.fn.plugin = function (options){
      var defaults = { posts:10, api: "http://myapi.com" }
      var settings = jQuery.extend({}, defaults, options);
      if(typeof options.username == 'undefined') { 
        alert("You must specify a username");
        return this;
      }
    }
    

    Edit – Missed part of the question, for the inaccessible ones, either have the values hard-coded, since that’s the same result, or a bit cleaner would be an internal object inside your plugin that is out of scope everywhere else. Again, not trivial to do on the same object unless you kept say an intenalDefaults object, and called jQuery.extend() with it after the extend of settings that so it would overwrite anything the consumer passed in.

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