Question

I’m currently converting a Delphi method used for random binary file access into Java. The Delphi procedure uses:

TSingleArray  = Array[0..MAXSIZE] of Single ... procedure GetLinkValues(const LinkVar: Integer;  const TimePeriod: Integer; var Value: PSingleArray); ... BlockRead(Fout, Value^, Nlinks*SizeOf(Single)); 

To read an array of bytes into an array of Single. Is there an equivalent way of doing this in Java without iterating through the array?

I’m currently using

List<Float> l = new ArrayList<Float>(); … for (int i = 0 ; i < nLinks ; i++ ) l.add( resultsFile.readFloat()); 

But I’m concerned about speed. Endianness is not a problem.

Answer 1

Have you profiled the code and actually found it to be a problem? Something is going to have to loop… are you really sure this is a bottleneck in your code?

Having said all that, you should be able to use a FloatBuffer which I suspect does what you want. Unfortunately Sun’s JavaDoc is down, so I can’t easily link to or check the documentation at the minute.

To use a FloatBuffer, you’d probably want to:

• Create a FileChannel associated with the file (e.g. with FileInputStream.getChannel)
• Create a ByteBuffer
• Create a FloatBuffer wrapping the ByteBuffer, with ByteBuffer.asFloatBuffer
• Read into the ByteBuffer with FileChannel.read(byteBuffer)
• Read from the FloatBuffer

I’m not particularly familiar/comfortable with java.nio, so I hope this is all correct – but it’s likely to be pretty fiddly. Your current loop is almost certainly simpler, so I strongly suggest you check the performance of that first! You might want to wrap your current FileInputStream in a BufferedInputStream, btw.