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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:47:39+00:00 2026-05-14T08:47:39+00:00

I’m currently given three values in a table A date value in the format

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I’m currently given three values in a table

A date value in the format of %dd-%mname-%yy (i.e 06-may-05), and am parsing that using Date.parse(input,true) to fix the issue with the leading values.

I’m then given a time value in the form of %hh:%mm:%ss.%ms (the ms of which I can take or leave) and a third value of a GMT offset.

I can’t really see anyway to convert these three values into a single DateTime object that would allow me to manipulate it using the range of ruby tools without first parsing the second value to time, somehow changing the offset ((given as a + or – n value) as in +2 or -6)to a signed int and then applying it and then parsing this all to a super dateTime object.

There’s got to be a better way. Is there?

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:47:39+00:00Added an answer on May 14, 2026 at 8:47 am

    Okay in order to create a dateTime value with the time and the date given and to take into account an offset you need the following code

    d =  DateTime.parse(dateVal+" "+TimeVal)
          offset = Rational(offset_val,24)
          d = d.new_offset(offset)
    

    So take your date, given to you as say 05 May 2010 and a timeval in the form hh:mm:ss

    With an offset of +- any value, for this instance say -8

    Then this code will generate you a new date object, offset to the amount you require

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