Question

I’m currently learning on how to use the Python optparse module. I’m trying the following example script but the args variable comes out empty. I tried this using Python 2.5 and 2.6 but to no avail.

import optparse

def main():
  p = optparse.OptionParser()
  p.add_option('--person', '-p', action='store', dest='person', default='Me')
  options, args = p.parse_args()

  print '\n[Debug]: Print options:', options
  print '\n[Debug]: Print args:', args
  print

  if len(args) != 1:
    p.print_help()
  else:
    print 'Hello %s' % options.person

if __name__ == '__main__':
  main() 

Output:

>C:\Scripts\example>hello.py -p Kelvin

[Debug]: Print options: {'person': 'Kelvin'}

[Debug]: Print args: []

Usage: hello.py [options]

Options:
-h, –help show this help message and exit
-p PERSON, –person=PERSON

Answer 1

The args variable holds any arguments that were not assigned to an option. Your code is indeed working properly by assigning Kelvin to the person option variable.

If you tried running hello.py -p Kelvin file1.txt, you would find that person still was assigned the value "Kelvin", and then your args would contain "file1.txt".

See also the documentation on optparse:

parse_args() returns two values:

• options, an object containing values for all of your options—e.g. if --file takes a single string argument, then options.file will be the filename supplied by the user, or None if the user did not supply that option
• args, the list of positional arguments leftover after parsing options