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Home/ Questions/Q 7620163
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T03:52:21+00:00 2026-05-31T03:52:21+00:00

I’m currently struggling with the following code, the intent of which is to implement

  • 0

I’m currently struggling with the following code, the intent of which is to implement variadic variadic template templates:

template
<
  template <typename... HeadArgs> class Head,
  template <typename... TailArgs> class...
>
struct join<Head<typename HeadArgs...>, Head<typename TailArgs...>...>
{
  typedef Head<typename HeadArgs..., typename TailArgs......> result;
};

Ideally, I’d be able to use this template metafunction to achieve the following:

template <typename...> struct obj1 {};
template <typename...> struct obj2 {};

typedef join
<
  obj1<int, int, double>, 
  obj1<double, char>,
  obj1<char*, int, double, const char*>
>::result new_obj1;

typedef join
<
  obj2<int, int, double>, 
  obj2<double, char>,
  obj2<char*, int, double, const char*>
>::result new_obj2;

/* This should result in an error, because there are 
   different encapsulating objects
typedef join
<
  obj1<int, int, double>, 
  obj1<double, char>,
  obj2<char*, int, double, const char*>
>::result new_obj;
*/

The output of the above would hopefully create new_obj1 and new_obj2 in the form template<int, int, double, double, char, char*, int, double, const char*> struct new_obj[1|2] {};

I’m using gcc 4.6.2 on Windows, which outputs an “expected parameter pack before ‘…'” for the expansion of “Head<typename TailArgs...>…”.

This error is reproducable with gcc 4.5.1.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T03:52:22+00:00Added an answer on May 31, 2026 at 3:52 am

    Try something like this:

    template <typename...> struct join;
    
    template <template <typename...> class Tpl,
              typename ...Args1,
              typename ...Args2>
    struct join<Tpl<Args1...>, Tpl<Args2...>>
    {
        typedef Tpl<Args1..., Args2...> type;
    };
    
    template <template <typename...> class Tpl,
              typename ...Args1,
              typename ...Args2,
              typename ...Tail>
    struct join<Tpl<Args1...>, Tpl<Args2...>, Tail...>
    {
         typedef typename join<Tpl<Args1..., Args2...>, Tail...>::type type;
    };
    
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