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I’m currently trying to learn assembly language (and the effects of different compiler options) by analyzing simple C code snippets. Now I stumpled across the following instruction:
mov %edx,-0x80(%rbp,%rax,4)
What I do not understand is the expression for the target address -0x80(%rbp,%rax,4).
The instruction assigns a value to a local array in a loop.
The machine command will copy the content of
%edxto the address given by%rbp + 4 * %rax - 0x80. It seems%raxis holding the index to that array and%rbp - 0x80is the base address.Take a look here to get a better understanding for the AT&T syntax.