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Home/ Questions/Q 7520145
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T02:00:57+00:00 2026-05-30T02:00:57+00:00

I’m currently trying to rexp a string into multiple variables. Example string: ryan_string =

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I’m currently trying to rexp a string into multiple variables. Example string:

ryan_string = "RyanOnRails: This is a test"

I’ve matched it with this regexp, with 3 groups:

ryan_group = ryan_string.scan(/(^.*)(:)(.*)/i)

Now to access each group I have to do something like this:

ryan_group[0][0] (first group) RyanOnRails
ryan_group[0][1] (second group) :
ryan_group[0][2] (third group) This is a test

This seems pretty ridiculous and it feels like I’m doing something wrong. I would be expect to be able to do something like this:

g1, g2, g3 = ryan_string.scan(/(^.*)(:)(.*)/i)

Is this possible? Or is there a better way than how I’m doing it?

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  1. Editorial Team
    Editorial Team
    2026-05-30T02:00:57+00:00Added an answer on May 30, 2026 at 2:00 am

    You don’t want scan for this, as it makes little sense. You can use String#match which will return a MatchData object, you can then call #captures to return an Array of captures. Something like this:

    #!/usr/bin/env ruby
    
    string = "RyanOnRails: This is a test"
    one, two, three = string.match(/(^.*)(:)(.*)/i).captures
    
    p one   #=> "RyanOnRails"
    p two   #=> ":"
    p three #=> " This is a test"
    

    Be aware that if no match is found, String#match will return nil, so something like this might work better:

    if match = string.match(/(^.*)(:)(.*)/i)
      one, two, three = match.captures
    end
    

    Although scan does make little sense for this. It does still do the job, you just need to flatten the returned Array first. one, two, three = string.scan(/(^.*)(:)(.*)/i).flatten

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