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Editorial Team
Asked: May 13, 20262026-05-13T21:44:36+00:00 2026-05-13T21:44:36+00:00

I’m currently trying to run a certain procedure (sql 2005) in VB6, passing some

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I’m currently trying to run a certain procedure (sql 2005) in VB6, passing some parameters:

Dim conn As Connection
Set conn = New Connection
conn.Open "Provider=whateverprovider;Data Source=whateversource;Database=whateverdatabase;User Id=whateverID;Password=whatever"
Dim CMD As ADODB.Command
Dim rs As ADODB.Recordset
Set CMD = New ADODB.Command
Set CMD.ActiveConnection = conn
CMD.CommandType = adCmdStoredProc
CMD.Parameters.Append CMD.CreateParameter("@EmpresaCNPJ", adVarChar, adParamInput, 14, "64687015000152")
CMD.Parameters.Append CMD.CreateParameter("@EntradaSaida", adChar, adParamInput, 1, "S")
CMD.Parameters.Append CMD.CreateParameter("@Participante", adVarChar, adParamInput, 60, "0000000020")
CMD.Parameters.Append CMD.CreateParameter("@nroNotaFiscal", adInteger, adParamInput)
CMD.Parameters("@nroNotaFiscal").Value = 2289
CMD.Parameters.Append CMD.CreateParameter("@serieNotaFiscal", adSmallInt, adParamInput)
CMD.Parameters("@serieNotaFiscal").Value = 1
Set rs = CMD.Execute

In the last line i get the following error message:

alt text http://dl.dropbox.com/u/3045472/ERRO.png

Which in English it reads:
“syntax error or access violation”

This message is REALLY generic, and I don’t have a clue about where could the problem be.

What did i do wrong ?

Here is the parameter receiving part of the sql code in the procedure:

   @EmpresaCNPJ varchar(14), 
   @EntradaSaida char(1)=null, 
   @Participante varchar(60)=null, 
   @nroNotaFiscal int=null, 
   @serieNotaFiscal smallint=null, 
   @EtapaInicial tinyint=null, 
   @LineComplement varchar(255)=null 

I was told that not every parameter should be passed, and that it should work with just five (out of seven).

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:44:36+00:00Added an answer on May 13, 2026 at 9:44 pm

    Where are you setting the name of the stored procedure?
    cmd.CommandName = ....

    EDIT: Set the CommandName to the name of the stored procedure, before you begin to call Parameters.Append

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