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Home/ Questions/Q 7526403
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T03:49:10+00:00 2026-05-30T03:49:10+00:00

I’m currently trying to send data via POST to a server, and the server

  • 0

I’m currently trying to send data via POST to a server, and the server is handling the data and appends it to a JSON file. I’m currently getting a 422 error and I’ve been receiving it for a while now. My question is: How do I receive that JSON error itself in Java so that I can see what the error is. All I’m seeing is a HttpResponseException and it doesn’t give me anything else. Thanks for the time and help in advance.

        HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(mPath);
        // Add your data
    try
    {
        List nameValuePairs = new ArrayList(4);
        httppost.setHeader("Authorization", Base64.encodeToString(new StringBuilder(bundleId).append(":").append(apiKey).toString().getBytes("UTF-8"), Base64.URL_SAFE|Base64.NO_WRAP));
        nameValuePairs.add(new BasicNameValuePair("state", "CA"));
        nameValuePairs.add(new BasicNameValuePair("city", "AndDev is Cool!"));
        nameValuePairs.add(new BasicNameValuePair("body", "dsads is assrawstjljalsdfljasldflkasjdfjasldjflasjdflkjaslfggddsfgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfddjflaskjdfkasjdlfkjasldfkjalskdjfajasldfkasdlfjasljdflajsdfjasdjflaskjdflaksjdfljasldfkjasljdflajsasdlfkjasldfkjlas!"));
        nameValuePairs.add(new BasicNameValuePair("title", "dsaghhhe fd!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        //HttpResponse response = httpclient.execute(httppost);
        //int status = response.getStatusLine().getStatusCode();
        ResponseHandler<String> responseHandler = new BasicResponseHandler();
        String responseBody = httpclient.execute(httppost, responseHandler);
        Log.v(TAG, "response: " + responseBody);
        //JSONObject response = new JSONObject(responseBody); 
        int f = 0;
    }
    catch(HttpResponseException e)
    {
        Log.e(TAG, e.getLocalizedMessage());
        Log.e(TAG, e.getMessage());
        e.printStackTrace();
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T03:49:12+00:00Added an answer on May 30, 2026 at 3:49 am

    you may send your parameters more conveniently by using predefined Json class as below:

        String jsonParam = null;
        try{
            JSONObject param = new JSONObject();
            param.put("state", "CA");
            param.put("city", "AndDev is Cool!");
            //and so on with other parameters
    
            jsonParam = param.toString();
        }
        catch (Exception e) {
            // TODO: handle exception
        }
    

    and set the post entity as:

    if(jsonParam != null)
         httppost.setEntity(new StringEntity(jsonParam, HTTP.UTF_8));
    
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