Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 349885
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T11:29:59+00:00 2026-05-12T11:29:59+00:00

I’m currently using the jar-with-dependencies assembly to create such a jar. However, the name

  • 0

I’m currently using the jar-with-dependencies assembly to create such a jar. However, the name of my jar is a bit long.

Since this jar is being used by RPG programs on an AS400, I’d like to shorten it to make life a bit easier for those developers. But, other than by hand, I’ve not found a way to rename the jar from the usual project-name-version-classifier-jar-with-dependencies.jar. I’d like something like project-name-version-classifier-full.jar

Is there anyway to do this without basically copying the jar-with-dependencies assembly descriptor and calling it full?

Additionally, I want to continue to have the jar without the classpath assembled stored in the repository.

I need two artifacts. The jar with my classifier holding the region which the build is for. The jar with all dependencies which also includes the region.

project-name-version-region-full.jar and project-name-version-region.jar should be stored in the repository. In the first example the classifier is region-full, in the 2nd it’s region. The latter is working.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T11:29:59+00:00Added an answer on May 12, 2026 at 11:29 am

    You can specify the finalName property to give the jar the name you want, and specify that appendAssemblyId should be false to avoid the “jar-with-dependencies” suffix.

    The configuration below will output a jar called “test.jar”

    <plugin>
      <artifactId>maven-assembly-plugin</artifactId>
      <version>2.2-beta-4</version>
      <executions>
        <execution>
          <id>jar-with-dependencies</id>
          <phase>package</phase>
          <goals>
            <goal>single</goal>
          </goals>
          <configuration>
            <descriptorRefs>
              <descriptorRef>jar-with-dependencies</descriptorRef>
            </descriptorRefs>
            <finalName>test</finalName>
            <appendAssemblyId>false</appendAssemblyId>
          </configuration>
        </execution>
      </executions>
    </plugin>
    

    Update: based on your comments, using the built-in descriptor won’t work . I believe this is down to a bug in the recent versions of the assembly-plugin – they’ve removed support for classifiers, but the id is fixed if you use a built-in descriptor, so you end up with a big daft name.

    As a workaround, you can copy the assembly descriptor used by the jar-with-dependencies descriptor and modify the id.

    This example would result in the assembly id being appended to the finalName, so if you need to have a name of region-full.jar, you can specify the finalName as region and the assembly id as full. This will result in a file in target called region-full.jar, but note it will still be installed to the Maven repository as an attached artifact with full used as the classifier. As long as this id is different to that for your other assembly there should be no collision though.

    The pom configuration would look like this.

    <plugin>
      <artifactId>maven-assembly-plugin</artifactId>
      <version>2.2-beta-4</version>
      <executions>
        <execution>
          <id>jar-with-dependencies</id>
          <phase>prepare-package</phase>
          <goals>
            <goal>single</goal>
          </goals>
          <configuration>
            <descriptors>
              <descriptor>src/main/assembly/jar-assembly.xml</descriptor>
            </descriptors>
            <finalName>region</finalName>
          </configuration>
        </execution>
      </executions>
    </plugin>
    

    and the jar-assembly.xml in src/main/assembly like this:

    <assembly>
      <id>full</id>
      <formats>
        <format>jar</format>
      </formats>
      <includeBaseDirectory>false</includeBaseDirectory>
      <dependencySets>
        <dependencySet>
          <unpack>true</unpack>
          <scope>runtime</scope>
        </dependencySet>
      </dependencySets>
      <fileSets>
        <fileSet>
          <directory>${project.build.outputDirectory}</directory>
        </fileSet>
      </fileSets>
    </assembly>
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
link Im having trouble converting the html entites into html characters, (&# 8217;) i
That's pretty much it. I'm using Nokogiri to scrape a web page what has
For some reason, after submitting a string like this Jack’s Spindle from a text
Basically, what I'm trying to create is a page of div tags, each has
this is what i have right now Drawing an RSS feed into the php,
I am reading a book about Javascript and jQuery and using one of the
I want use html5's new tag to play a wav file (currently only supported
I have this code to decode numeric html entities to the UTF8 equivalent character.

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.