Question

I’m currently using the pattern: \b\d+\b, testing it with these entries:

numb3r 
2
3454 
3.214
test

I only want it to catch 2, and 3454. It works great for catching number words, except that the boundary flags (\b) include "." as consideration as a separate word. I tried excluding the period, but had troubles writing the pattern.

Basically I want to remove integer words, and just them alone.

Answer 1

You could use lookaround instead if all you want to match is whitespace:

(?<=\s|^)\d+(?=\s|$)