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Home/ Questions/Q 603389
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:55:32+00:00 2026-05-13T16:55:32+00:00

I’m currently working on creating an Assembly with virtual properties. The examples on MSDN

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I’m currently working on creating an Assembly with virtual properties. The examples on MSDN are only creating normal properties. How do I create a class inside an assembly which has virtual properties?

I would like to be able to generate a class like this:

    public class ClassA
    {
        public virtual int Id { get; set; }
        public virtual string Name { get; set; }
        public virtual string ClassName { get; set; }
        public virtual ClassB Partner { get; set; }
    }

    public class ClassB
    {
        public virtual int Id { get; set; }
        public virtual string Name { get; set; }
    }

The PropertyBuilder class doesn’t have PropertyAttributes.Virtual, so I don’t know how to create a virtual property. If I create this class in Visual Studio myself, and then open it in Reflector, the properties themselfes are virtual, so it is possible.

How can it be done?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:55:33+00:00Added an answer on May 13, 2026 at 4:55 pm

    Here’s an example of creating a class at runtime that contains a single integer property Id which is virtual:

    class Program
    {
        static void Main(string[] args)
        {
            var aName = new AssemblyName("DynamicAssemblyExample");
            var ab = AppDomain.CurrentDomain.DefineDynamicAssembly(aName, AssemblyBuilderAccess.Run);
            var mb = ab.DefineDynamicModule(aName.Name);
            var tb = mb.DefineType("MyDynamicType", TypeAttributes.Public);
            var fbId = tb.DefineField("_id", typeof(int), FieldAttributes.Private);
            var pbId = tb.DefineProperty("Id", PropertyAttributes.HasDefault, typeof(int), null);
    
            var getSetAttr = MethodAttributes.Public | MethodAttributes.SpecialName | MethodAttributes.HideBySig | MethodAttributes.Virtual;
    
            var mbIdGetAccessor = tb.DefineMethod("get_Id", getSetAttr, typeof(int), Type.EmptyTypes);
    
            var numberGetIL = mbIdGetAccessor.GetILGenerator();
            numberGetIL.Emit(OpCodes.Ldarg_0);
            numberGetIL.Emit(OpCodes.Ldfld, fbId);
            numberGetIL.Emit(OpCodes.Ret);
    
            var mbIdSetAccessor = tb.DefineMethod("set_Id", getSetAttr, null, new Type[] { typeof(int) });
    
            var numberSetIL = mbIdSetAccessor.GetILGenerator();
            numberSetIL.Emit(OpCodes.Ldarg_0);
            numberSetIL.Emit(OpCodes.Ldarg_1);
            numberSetIL.Emit(OpCodes.Stfld, fbId);
            numberSetIL.Emit(OpCodes.Ret);
    
            pbId.SetGetMethod(mbIdGetAccessor);
            pbId.SetSetMethod(mbIdSetAccessor);
    
            var t = tb.CreateType();
            var instance = Activator.CreateInstance(t);
            Console.WriteLine(t.GetProperty("Id").GetGetMethod().IsVirtual);
        }
    }
    

    The reason you don’t find anything related to virtual in the PropertyBuilder is because properties don’t have this concept. Methods can be virtual, so when you declare a virtual property you are declaring virtual getter and setter methods. Take a look at MethodAttributes enumeration.

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