Question

I’m designing a template creation tool, which uses a jQuery Ajax request that posts parameters to a PHP file. The PHP does the actual generation of the template’s HTML.

// Send for processing. Expect JS back to execute.
function generate() {
$.ajax({
    type: "POST",
    url: "generate.php",
    data: $('#genform :input').serialize(),
    dataType: "script",
    beforeSend: function() {
        $("#loading").html("<img src='images/loadbar.gif' />");
        $("#loading")           
        .dialog({
            height: 80,
            width: 256,
            autoOpen: true,
            modal: true
        });
    },
    success: function(data) {
        $("#loading").dialog('close');
    }
});
}

My trouble is that I have the ajax dataType: set to “script”. Using this, the PHP file generates some jQuery dialogs for any errors which works nicely. However, after I generate the HTML, i’m having trouble passing it back.

So I have probably 100 lines of generated HTML and javascript which i’d like to work with.
In the PHP file, i’ve tried:

echo('$("#result").html("'.$html.'");');

This does actually work if there are NO line breaks in $html. As soon as there are any line breaks, the Chrome debugger reports “gen.html:1 Uncaught SyntaxError: Unexpected token ILLEGAL”. It’s obvious that it’s trying to eval the returned response headers, but is stopping at any line break.

So, to be clear, when I pass $html back, if the contents are this:

$html = "<div>hi there</div>";

It works fine (all of my error message dialogs are one line). But if it’s:

$html = "<div>
           hi there
         </div>";

It blows up.

I’m really not sure how to get around this, or if there’s a better way to go about it. It’s important to me to keep the formatting so people can copy the HTML template.

I may just break down and display the template file on the PHP page if I can’t solve this, but I was really hoping to keep everything within the confines of the HTML page.

Answer 1

Another simple way (similar to the xml solution) is to have a JSON response encoded as an object. This is naturally supported by jQuery, which actually decodes the JSON for you as well. It involves using:

1. Replace dataType: "script" with datatype: "json"
2. Change the success function to do the html replacement.
3. Change the PHP to simply output the json_encode($html);

Here’s the changed success function

success: function(data) {
    $("#loading").dialog('close');
    $("#result").html(data.result_html);
}

Here’s the changed PHP function:

echo json_encode(array('result_html' => $html));

I prefer not to directly output the HTML so you can add extra data to the JSON output in the future, but you can also simply do $("#result").html(data); with the PHP echo json_encode($html);