Home/ Questions/Q 212937
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-11T18:13:57+00:00

i’m developing a java application using the jstun library (hxxp://jstun.javawi.de/), and i need to

  • 0

i’m developing a java application using the jstun library (hxxp://jstun.javawi.de/), and i need to compare my public ip with the one chosen by the kernel (wildcard address – hxxp://java.sun.com/j2se/1.5.0/docs/api/java/net/DatagramSocket.html#DatagramSocket() ) when i create a udp socket.

what i don’t understand is, if my local ip on my natted network is in the form of 192.168.1.x, why do i get an ip such as 10.x.x.x ?

is there a particular reason why the two are totally unrelated?
if i wasn’t behind a nat, would the kernel bind the socket to my public address?

thanks a lot!
asymmetric

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    i failed to mention a rather important thing: i’m developing for android, and running my code on the android emulator, which explains the 10.x.x.x address thing..

    i should dig deeper into that.. thanks for the help!

    for those that are interested: hxxp://developer.android.com/guide/developing/tools/emulator.html#networkaddresses

    • 0