Home/ Questions/Q 7648367
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-31T10:41:53+00:00

I’m developing a simple sistem so our employees could save their overtime so, at

  • 0

I’m developing a simple sistem so our employees could save their overtime so, at the end of the month, they’re payed for those extra hours they made.

Normal hours are counted as 1 but nightly ones (through 23:00 to 07:00) should be 1,25 hours each.

That said, we’re requesting to introduce the day, and the start and end hours. So, I thought I could have an array like this:

$hours= array(
    '0' => true, '1' => true, '2' => true, '3' => true, '4' => true, '5' => true, '6' => true, 
    '7' => false, '8' => false, '9' => false, '10' => false, '11' => false, '12' => false, '13' => false,
    '14' => false, '15' => false, '16' => false, '17' => false, '18' => false, '19' => false, '20' => false,
    '21' => false, '22' => false,  '23' => true
);

So, basically I test if an hour is special or it isn’t with a loop like this:

$normals = 0;
$specials = 0;
$hour_since = '23:00:00';
$hour_since_expl = explode(':',$hour_since);
$hour_to = '23:15:00';
$hour_to_expl= explode(':',$hour_to );
$date = $fecha = '2012-03-14';
$datetime_since= strtotime($date ." ".$hour_since );
$datetime_to= ((int) $hour_to_expl[0] > (int) $hour_to_expl[0]) ?
        strtotime(date("Y-m-d h:i:s", strtotime($date ." ".$hour_to)) . " +1 day") :
        strtotime($date." ".$hour_to);

$difference = $datetime_to - $datetime_since;
$hours_difference = $difference / SECONDS_PER_HOUR; //60*60
    for ($i = 0; $i <= $difference; $i++){
        $hour = $i + (int) $hour_since_expl [0];
        if ($hours[$hour]) //Special hour here... Pay more!
            $specials++;
        else
            $normals++;
    }

But the problem is when hours are not exact and you have started somewhere like 22:30 and ended 00:30 where you have 0,5 hours being not special. I’ve been struggling my mind but I can’t find any solution.

Do someone have any ideas?

Edit: More code given.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Let’s assume that start time is 15:15 and endtime is 22:45. First, convert start time to nearest HOUR on or after it and endtime to nearest HOUR on or before it. So we get 15:00 and 22:00. Use your loop for these hours and use the differences as follows: if the difference time (15:15-15:00 or 22:45-22:00) is in overtime, then do overtime*numMins/60 else do standard*numMins/60. I’m not familiar with PHP, so had to do this in pseudo code

    • 0