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Home/ Questions/Q 7981589
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T10:25:23+00:00 2026-06-04T10:25:23+00:00

I’m developing an application in python with django. User can upload a CSV file.

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I’m developing an application in python with django. User can upload a CSV file. I use file upload to get the file. But, it’s not stored any where. I try to take it from request to process the file. While I’m trying to open the file, it gives an error. I use the CSV library exists in python to process. Form elements and attributes used as per django. Request object which I try to take the uploaded file is also django designed object.

import csv
from rootFolder.UploadFileForm

def uploadFile(request):
    if request.method == 'POST':
        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            paramFile = open(request.FILES['uploadFile'], 'rb')
            portfolio = csv.DictReader(paramFile)
            users = []
            for row in portfolio:
                users.append(row)

This below line gives the error.

paramFile = open(request.FILES['uploadFile'], 'rb')

The given error is :

TypeError: coercing to Unicode: need string or buffer, InMemoryUploadedFile found

Please kindly give your suggestion if you got any idea on this.
Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-06-04T10:25:24+00:00Added an answer on June 4, 2026 at 10:25 am

    open() takes the name of the file as the argument and not the file object itself.

    Can you try something like this:

    paramFile = request.FILES['uploadFile'].read()
    portfolio = csv.DictReader(paramFile)
    
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