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Home/ Questions/Q 8901899
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Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T01:28:31+00:00 2026-06-15T01:28:31+00:00

I’m developing an application which displays Phone contacts with CursorAdapter. When I run it,

  • 0

I’m developing an application which displays Phone contacts with CursorAdapter.
When I run it, I faced with a list view which repeated just one contact as bellow
(“david” is one of my contacts, just repeated in listview)

david
017224860

david
017224860

david
017224860

david
017224860

david
017224860

david
017224860
.

.

.

.

My activity looks like

public class Contacts extends Activity {    
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.contacts);

    Cursor cursor = getContentResolver()
        .query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
               null, null, null, null);

    startManagingCursor(cursor);

    ContactCursorAdapterCT adapter= new ContactCursorAdapterCT(Contacts.this, cursor);
     ListView contactLV = (ListView) findViewById(R.id.listviewblcontactsDB);

    contactLV.setAdapter(adapter);

And my cursorAdapter looks like:

public class ContactCursorAdapterCT extends CursorAdapter {
       public ContactCursorAdapterCT(Context context, Cursor c) {
    super(context, c);
    // TODO Auto-generated constructor stub
}

@Override
public void bindView(View view, Context context, Cursor cursor) {

    while (cursor.moveToNext()) {

        TextView name = (TextView)view.findViewById(R.id.blacklistDB1);               
          name.setText(cursor.getString(cursor.getColumnIndex
          (ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME)));

        TextView phone = (TextView)view.findViewById(R.id.blacklistDB2); 
          phone.setText(cursor.getString(cursor.getColumnIndex
          (ContactsContract.CommonDataKinds.Phone.NUMBER)));

    }
}

@Override
public View newView(Context context, Cursor cursor, ViewGroup parent)
{
    // TODO Auto-generated method stub

    LayoutInflater inflater = LayoutInflater.from(context);

    View v = inflater.inflate(R.layout.lv, parent, false);
            bindView(v, context, cursor);
           return v;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T01:28:33+00:00Added an answer on June 15, 2026 at 1:28 am

    I noticed a few points:

    1. A CursorAdapter moves the Cursor for you, take out your call to cursor.moveToNext().
    2. The adapter’s getView() calls newView() and bindView() on it’s own; you shouldn’t call these methods yourself.
    3. You should watch the Android developer’s lectures at Google IO to learn tips and tricks about speeding up your adapter. Tips like:
      • Using a ViewHolder, rather than calling findViewById() repeatedly.
      • Saving the indices of your Cursor, rather than calling getColumnIndex() repeatedly.
      • Fetching the LayoutInflater once and keeping a local reference.
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