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Home/ Questions/Q 8561895
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T16:36:28+00:00 2026-06-11T16:36:28+00:00

I’m developing an ASP.NET web app using VS2010,C#, I want to display a file

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I’m developing an ASP.NET web app using VS2010,C#, I want to display a file upload control when my users click on a hyperlink (or label, it doesn’t differ), and then the upload operation should be performed, I have no problem working with upload control, but currently I have an invisible upload control which display it using JavaScript in my hyperlink onclick function, the upload control is displayed but I don’t know how the get the uploaded file, how should I perform this operation? I want to display upload file dialog when my users click on a label or hyperlink, then they can select their file and the file should be uploaded, and finally I should be able to work with this file in server side (I’m going to get file stream and store it in SQL), what are my options? JQuery? Ajax? JavaScript? or something else?

my JavaScript function:

function OpenFile()
{
document.getElementById("<%=fu.ClientID%>").style.display="";
var result = document.getElementById("<%=fu.ClientID%>").click();
document.getElementById("<%=fu.ClientID%>").style.display="none";
return false;
}

and my markup:

<asp:FileUpload ..... style="display:none;"....>
    <ASP:hyperlink onclick="OpenFile();"...../>
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  1. Editorial Team
    Editorial Team
    2026-06-11T16:36:29+00:00Added an answer on June 11, 2026 at 4:36 pm

    After you select a file and do a PostBack, you can access the file as follows

    <asp:FileUpload ID="FileUpload1" ..... style="display:none;"....>
    

    Access the underlying posted file using the PostedFile

        var fileLen = FileUpload1.PostedFile.ContentLength;
        Byte[] Input = new Byte[fileLen];
        myStream = FileUpload1.FileContent;
        myStream.Read(Input, 0, fileLen);
    

    Or just save it on the server:

    FileUpload1.SaveAs(savePath);
    
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