Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6625231
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T21:44:56+00:00 2026-05-25T21:44:56+00:00

I’m devloping a music streaming site where I have two major tables: ‘activity’ and

  • 0

I’m devloping a music streaming site where I have two major tables: ‘activity’ and ‘music’. Activity saves, among other things, every song reproduction into a new record.

Every time I select from music I need to fetch the number of reproductions of every song. So, what would be the better practice

    SELECT music.song, music.artist, COUNT (activity.id) AS reproductions 
FROM music LEFT JOIN activity USING (song_id) WHERE music.song_id = XX 
GROUP BY music.song_id

Or would it be better to save the number of reproductions into a new field in the music table and query this:

SELECT song, artist, reproductions FROM music WHERE music.song_id = XX

This last query is, of course, much easier. But to use it, every time I play a soundfile I should make two querys: one INSERT in the activity table, and one UPDATE on the reproductions field on music table.

What would be the better practice in this scenario?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T21:44:56+00:00Added an answer on May 25, 2026 at 9:44 pm

    Well this depends on the response times these two queries will have in time.

    After tables will become huge (hypothetically) sql nr 2 will be better.

    You have to think that in time even insert might be costly…you you might think on some data warehousing if you will have ..millions of rows in DB.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I have a French site that I want to parse, but am running into
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I have just tried to save a simple *.rtf file with some websites and
I have a jquery bug and I've been looking for hours now, I can't
this is what i have right now Drawing an RSS feed into the php,
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I have this code: - (void)parser:(NSXMLParser *)parser foundCDATA:(NSData *)CDATABlock { NSString *someString = [[NSString
I have a text area in my form which accepts all possible characters from
I have an MVC Razor view @{ ViewBag.Title = Index; var c = (char)146;

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.