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Home/ Questions/Q 7692293
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T20:49:14+00:00 2026-05-31T20:49:14+00:00

I’m doing a BigInt implementation in C++ and I’m having a hard time figuring

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I’m doing a BigInt implementation in C++ and I’m having a hard time figuring out how to create a converter from (and to) string (C string would suffice for now).

I implement the number as an array of unsigned int (so basically putting blocks of bits next to each other). I just can’t figure out how to convert a string to this representation.

For example if usigned int would be 32b and i’d get a string of “4294967296”, or “5000000000” or basically anything larger than what a 32b int can hold, how would I properly convert it to appropriate binary representation?

I know I’m missing something obvious, and I’m only asking for a push to the right direction. Thanks for help and sorry for asking such a silly question!

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  1. Editorial Team
    Editorial Team
    2026-05-31T20:49:15+00:00Added an answer on May 31, 2026 at 8:49 pm

    Well one way (not necessarily the most efficient) is to implement the usual arithmetic operators and then just do the following:

    // (pseudo-code)
    // String to BigInt
    
    String s = ...;
    BigInt x = 0;
    
    while (!s.empty())
    {
        x *= 10;
        x += s[0] - '0';
        s.pop_front();
    }
    
    Output(x);
    
    // (pseudo-code)
    // BigInt to String
    
    BigInt x = ...;
    String s;
    
    while (x > 0)
    {
        s += '0' + x % 10;
        x /= 10;
    }
    
    Reverse(s);
    Output(s);
    

    If you wanted to do something trickier than you could try the following:

    1. If input I is < 100 use above method.
    2. Estimate D number of digits of I by bit length * 3 / 10.
    3. Mod and Divide by factor F = 10 ^ (D/2), to get I = X*F + Y;
    4. Execute recursively with I=X and I=Y
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