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Home/ Questions/Q 932349
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T20:39:12+00:00 2026-05-15T20:39:12+00:00

I’m doing a pretty basic string matching test as follows: if(msList.indexOf(textChoice) != -1) This

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I’m doing a pretty basic string matching test as follows:

if(msList.indexOf(textChoice) != -1)

This works well except that occasionally the sub-string I’m looking for (textChoice) ends with an asterisk. Then I end up getting false matches because the asterisk in the string is interpreted as an operator, not a character in the string.

So how can I do this test so that any asterisks in the sub-string are treated as regular characters?

PS. I know the simple answer is “Don’t include asterisks in your sub-string” but they’re in the data I’m working with–I can’t get rid of them.

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:39:13+00:00Added an answer on May 15, 2026 at 8:39 pm

    All characters in the substring will be treated as regular characters. * is not a special operator and does not change the behavior of indexOf in any way. Moreover, the indexOf method should never return false. It will return:

    • -1 if no match is found or
    • starting index of matching substring if found

    Note that the starting index can be 0 which does not equate to false for substring searching. It just means that the substring was found in the beginning of the string.

    "ABC".indexOf("AB") // 0
    

    Put explicit checks comparing the return value with -1 instead of just checking for a truthy value.

    if("ABC".indexOf("AB")) {
        // will never execute
    }
    

    Instead, always do this:

    if("ABC".indexOf("AB") != -1) {
       // ..
    }
    
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