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Home/ Questions/Q 6159165
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:05:10+00:00 2026-05-23T21:05:10+00:00

I’m doing an Invoice system, and i’m facing a problem. Imagine a simple Invoice,

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I’m doing an Invoice system, and i’m facing a problem.

Imagine a simple Invoice, where you have rows (lines, tuples, whatever) where you place the thing you’re buying, the amount, the price, etc.

So, in my script i’ve a form like this:

<form action='I-process-the-form-but-not-see-data.php'>
   <input ... //some other imputs (client,date,etc)

   <table>
   //table hedaers
      <tr>
      <td><input type='text' name='invoiceData[0][name]' /></td>
      <td><input type='text' name='invoiceData[0][amount]' /></td>
      <td><input type='text' name='invoiceData[0][price]' /></td>
   </tr>
</form>

I provide a button that adds a line to the invoice. I’m doing it with JQuery.

I first get the first and clone it. Replace invoiceData[0] with invoiceData[COUNTER] (Global counter) and everything looks great.

The problem is that my data is not being sent to the php script. The only data i get is the inputs that are static (first loaded). Not the one that i add with jquery.

I’ve inspect it with firebug and it’s adding the new lines ok.

Actually, if i paste the code generated by JQuery in the static form it sends it well.

What could be happening?

EDIT (JQUERY MAGIC):

var clon = $("#selectorForTR").clone().html(); //there is a minimal workaround for this but doesn't matters
clon = $(html.replace(/invoiceData\[0\]/ig, "invoiceData["+contador+"]"));
$("#tableBody").append(clon);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:05:12+00:00Added an answer on May 23, 2026 at 9:05 pm

    Make sure you are opening and closing your cloned tr, i think that is why it is only getting one row.

    <tr> ...html... </tr>
    

    See my example : http://jsfiddle.net/wADef/

    Changed it a bit to work in jsFiddle, but check it out and let me know.

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