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Asked: 2026-05-11T06:47:09+00:00

I’m doing some testing to ensure that the all in one zip file that

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I’m doing some testing to ensure that the all in one zip file that i created using a script file will produce the same output as the content of a few zip files that i must manually click and create via web interface. Therefore the zip will have different folder structure.

Of course i can manually extracted them out and using my powerful eyeball technique to scan them or even lazier i can write a script to do that, but before i invest more time and get accused by my boss for company time robbery, i’m asking if there’s a better way to do this?

I’m using perl LAMP stack by the way. thanks.

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  1. You can use perl’s Archive::ZIP or Python’s zipfile to extract the filenames, sizes and CRC checksums of the files in the archives. Create a file which contains the results sorted by file name (ignore the path).

    For your smaller ZIPs, merge the results of the script (cat list1 list2 list3 | sort).

    Now, you can use diff to compare the results.

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