Question

I’m doing something like this

Class.hpp:

 class Class {

 private:
     static const unsigned int arraySize;
     int ar[arraySize+2];
 };

Class.cpp:

#include <Class.hpp>
const unsigned int arraySize = 384;

The compiler (q++, a c++ compiler for the QNX OS based on g++) gives me error: array bound is not an integer constant while compiling a unit including Class.hpp (not while compiling Class.cpp).

Why isn’t that working? I know that a static const member can be used as an array bound, guaranteed by the C++ standard (see this anwser). But why doesn’t the compiler see the result of static const + const as a constant?

Answer 1

This is good code which should have been accepted by the compiler:

class Class { 
  const static int arraySize = 384; 
  int ar[arraySize+2]; 
}; 

and if it isn’t, your compiler is broken.

However, if you move actual constant out of the header file to selected translation unit, that invalidates the code.

// Class.h
class Class { 
  const static int arraySize;
  int ar[arraySize+2]; // ERROR
}; 

// Class.cpp
const int Class::arraySize = 384;

This is because the size of your Class object cannot be determined at compile time from the data available in the header alone. This is not exactly right reason, but reasoning along these lines helps to understand compilation errors such as this.

To avoid making such mistakes, you can replace static const int with an enum, e.g.

class Class { 
  enum { arraySize = 384 }; 
  int ar[arraySize+2]; 
};