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Home/ Questions/Q 703355
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T03:49:19+00:00 2026-05-14T03:49:19+00:00

I’m doing this query: SomeObject.objects.annotate(something=Avg(‘something’)).order_by(something).all() I normally have an aggregate field in my model

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I’m doing this query:

SomeObject.objects.annotate(something=Avg('something')).order_by(something).all()

I normally have an aggregate field in my model that I use with Django signals to keep in sync, however in this case perfomance isn’t an issue so I thought I’d keep it simple and just use subqueries.

This approach, however, presented an unexpected issue.
It all works great if aggregate function results are like:

[5.0, 4.0, 6.0 … (etc, just numbers)]

However if you mix in some None‘s than it is ordered like this:

[None, 5.0, 4.0 …]

The issue is that None has higher value than any number, while it should have value at most a value of 0.

I’m using PostgreSQL and haven’t tested w/ other DBs. I haven’t actually checked what query is generated etc.

I worked it around by just sorting in memory:

sorted(…, key=lambda _:_.avg_rating if _.avg_rating is not None else 0) 

So I’m just curious if there is a way to do it with just the Django ORM? Perhaps .where? Or something else?

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  1. Editorial Team
    Editorial Team
    2026-05-14T03:49:20+00:00Added an answer on May 14, 2026 at 3:49 am

    How about just adding a has_something=1,0 via extra() and then order on both has_something and something?

    with_avg = SomeObject.objects.annotate(avg=Avg('something'))
    with_avg_and_has = with_avg.extra(select={'has_something': 'something is NULL'})
    sorted_result = with_avg_and_has.order_by('-has_something', '-avg').all() 
    

    Not 100% ORM in the strictest sense but it does push the sorting back into the DB.

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