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Home/ Questions/Q 9031597
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T07:46:17+00:00 2026-06-16T07:46:17+00:00

I’m experimenting with MySQLi and using the following code to check differences for how

  • 0

I’m experimenting with MySQLi and using the following code to check differences for how I should approach my array formatting/usage for fetch_array(MYSQLI_ASSOC);

here is my code:

include "Database.php"; 

$ArrayQuery = $mysqli->query("SELECT * FROM accountinformation");


while ($ArrayResults = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
    echo count($ArrayResults);
    echo "<br>";
}
echo "<br><br><bR><br>";
    $Empty = array();
while ($ArrayResult = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
    foreach ($ArrayResult AS $ArrayRes)
    {
        $Empty[] = $ArrayRes;
    }
}

print_r($Empty);

The problem is, that i’m using the same Variable for my while loop, the first one returns 3 then 3 Which is expected.

But the problem is, with my second query; it returns a blank array

array( ) when print_r();

and when I do:

while ($ArrayResult = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
{
    print_r($ArrayResult);
}

For my Second while loop, it returns nothing for output.

I have checked my variables $ArrayResults and $ArrayResult are not duplicates, they are in fact unique.

Why is my second while loop returning nothing when my first one is working?

Update

When I produce a second query into the mixture with a different starting variable:

$ArrayQuer = $mysqli->query("SELECT * FROM accountinformation");

and modify my second while loop:

while ($ArrayResult = $ArrayQuer->fetch_array(MYSQLI_ASSOC))
{
    print_r($ArrayResult);
}

I get the expected output? So is it a case of MySQLi not allowing the same parameters to be used twice throughout the script?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T07:46:18+00:00Added an answer on June 16, 2026 at 7:46 am

    mysqli_data_seek

    Adjusts the result pointer to an arbitrary row in the
    result

    while ($ArrayResults = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
        {
            echo count($ArrayResults);
            echo "<br>";
        }
        echo "<br><br><bR><br>";
        mysqli_data_seek($ArrayQuery,0); // Addition Made Here
            $Empty = array();
        while ($ArrayResult = $ArrayQuery->fetch_array(MYSQLI_ASSOC))
        {
            foreach ($ArrayResult AS $ArrayRes)
            {
                $Empty[] = $ArrayRes;
            }
        }
        print_r($Empty);
    

    To re-use an already fetched array; you should use mysqli_data_seek(); (Notice I have added it above your `$Empty Variable) This should be the problem.

    See the manual here:

    http://us.php.net/manual/en/mysqli-result.data-seek.php

    Think of this scenario; Why would you re-buy something you already own?

    Fits perfectly in your case

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