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Home/ Questions/Q 8089217
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T19:20:09+00:00 2026-06-05T19:20:09+00:00

I’m extending a constructor class’ functionality via the prototype method, but I’m having trouble

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I’m extending a constructor class’ functionality via the prototype method, but I’m having trouble figuring out how to access the soon-to-be instance of the constructor class.

Lets say we have the following class:

Bla = function()
{
    this.a = 5;
}

Simple enough. Now, I will extend it with a very simple method…

Bla.prototype.f = function(){console.log("Abdf.")};

new Bla().f(); //Logs "Abdf as expected."

But, what if I wanted to access the a property (5)? Say I am trying to extend the constructor class like this:

Bla.prototype.f2 = function(b){return b * here_are_the_problems.a};

Apparently using this refers to something else. What should I use instead?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T19:20:11+00:00Added an answer on June 5, 2026 at 7:20 pm

    Use this to refer to the object on which the method was called…

    console.log(this.a);
    

    There are several ways the value of this can be set. One is that it generally refers to the object on which the function was called if the function was called as a method of the object.

    Bla = function()
    {
        this.a = 5;
    }
    
    
    Bla.prototype.f = function(){console.log(this.a)};
    
    var bla = new Bla();
    
    bla.f(); //Logs 5
    

    So you can see that since f was called as a method of the instance of Bla referenced by the bla variable, the value of this in f will be set to refer to that same object.

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