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Home/ Questions/Q 7439405
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:42:03+00:00 2026-05-29T10:42:03+00:00

I’m facing a tricky problem. I’d like to forge a C source file content

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I’m facing a tricky problem. I’d like to forge a C source file content according to compiler command line. For example(using VC):

If I use command line

cl -c -E -Dfoo=rice test.c

I wish to get actual C content (after preprocessing):

char *s = "rice";

If I use command line

cl -c -E -Dfoo=ball test.c

I wish to get actual C source file content:

char *s = "ball";

Now finding a solution…

FIRST TRY:

// test.c
#define STRNAME(n) #n
char *s = STRNAME(foo);

— No luck. No matter what foo is defined to be on command line, I always get

char *s = "foo"; // Oh no!

SECOND TRY (closest I can image, but still verbose):

// test.c
#define STRNAME(n) #n
char *s = foo;

This time, I have to change my command line verbosely:

cl -c -E -Dfoo=STRNAME(rice) test.c

Now I get

 char *s = "rice";

Is there a way to help me out of this verbosity?

BY the way: I really do not like to introduce quotes into command arguments (make them become part of argv[x], because you will not be able to write such command line reliably and portably on Windows CMD and Linux Bash — I think.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:42:04+00:00Added an answer on May 29, 2026 at 10:42 am

    You need an extra level of indirection in the preprocessor to expand your macro first. Something like:

    #define STRNAME1(n) #n
    #define STRNAME(n) STRNAME1(n)
    char *s = STRNAME(foo);
    

    This is a fairly common pattern, and results in your macro being expanded and then converted to a string, rather than just converted to a string.

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