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Home/ Questions/Q 6935397
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:05:51+00:00 2026-05-27T12:05:51+00:00

I’m facing a weird issue with PHP. This simple example: <?php $array = array(

  • 0

I’m facing a weird issue with PHP. This simple example:

<?php
$array = array(
  'zero',
  'one',
  'id' => 'two'
);

foreach ($array as $key => $value) {
  if ($key == "id") {
    echo "Key: ". $key .", value: ". $value ."\n";
  }
}
?>

should (imho) output this:

Key: id, value: two

But it outputs

Key: 0, value: zero
Key: id, value: two

How is this possible: 0 == "id"?

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:05:51+00:00Added an answer on May 27, 2026 at 12:05 pm

    When $key is 0 and gets compared to the string “id“, the string (“id“) will be converted to an integer. Since “id” can’t be turned into a valid integer that conversion will yield 0, and the if statement becomes true.

    Since you don’t want the implicit conversion to happen between two types who aren’t compatible use the more strict === version of ==. === will see if the variables are of the same type and has the same exact value.

     if ($key === "id") {
       ...
     }
    

    Documentation PHP: Comparison Operators


    Examples

    var_dump (0         == (int)"id");
    var_dump ((string)0 == "id");
    var_dump (0        === "id");
    
    var_dump (1.0 === 1);
    

    output

    bool(true)
    bool(false)
    bool(false)
    bool(false) # be careful!
    
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