Question

I’m facing something strange with a C++ code I’m working on. It’s about an “ofstream” object that I created in order to have the data I need in a file.

Anyways, I need to place this object, which I call output1 after an “if” condition. So, any data that passes the condition I want then in the file.

Now, if I put the usual “cout” after the condition:

.
.
if (Check == 0) cout << data1 << " " << data2 << endl;
.

I’ll get results printed on the screen.

But when I put my output1,

if (Check == 0) output1 << data1 << " " << data2 << endl;

then nothing is written in the file!

I have checked that my output1 object works fine somewhere else in the code. But not here! And the complier didn’t mention any error or lack of declaration.

Any ideas?

Note: I can’t put the code here, or even the relevant parts as it is a very long code and is not meant to be public, so I don’t have the right to copy it.

Answer 1

My crystal ball tells me you have two different objects both named output1.

The if statement definitely has no effect on the problem.