Question

I’m fairly naive in this regard. I’m not sure why my connection is timing out. Thanks in advance.

#!/usr/bin/env python
import socket

def socket_to_me():
    socket.setdefaulttimeout(2)
    s = socket.socket()
    s.connect(("192.168.95.148",21))
    ans = s.recv(1024)
    print(ans)

the trace back generated by this code

Traceback (most recent call last):
  File "logger.py", line 12, in <module>
    socket_to_me()
  File "/home/drew/drewPlay/python/violent/networking.py", line 7, in socket_to_me
    s.connect(("192.168.95.148",21))
  File "/usr/lib/python2.7/socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)
timeout: timed out

Answer 1

You don’t need to alter the default timeouts for all new sockets, instead you can just set the timeout of that particular connection. The value is a bit low though, so increasing it to 10-15 seconds will hopefully do the trick.

First, do this:

s = socket.socket()

Then:

s.settimeout(10)

And you should use “try:” on the connect, and add:

except socket.error as socketerror:
    print("Error: ", socketerror)

This will bring up the systems error message in your output and handle the exception.

Modified version of your code:

def socket_to_me():
    try:
        s = socket.socket()
        s.settimeout(2)
        s.connect(("192.168.95.148",21))
        ans = s.recv(1024)
        print(ans)
        s.shutdown(1) # By convention, but not actually necessary
        s.close()     # Remember to close sockets after use!
    except socket.error as socketerror:
        print("Error: ", socketerror)