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Home/ Questions/Q 6044591
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T07:01:45+00:00 2026-05-23T07:01:45+00:00

I’m fairly new to mysql and I was wondering if the following code should

  • 0

I’m fairly new to mysql and I was wondering if the following code should be working. I’ve been checking with my database after submission of this form and nothing is getting inputted into the database. Please let me know what I’m doing wrong, Thank you!

 <?php
$username = $_SESSION['username'];
$email = $_POST['email'];
$desc = $_POST['desc'];
$url = $_POST['url'];
$priority = $_POST['priority'];


        if( strlen($username) > 0 && strlen($email) > 0 && strlen($desc) > 0)
        {
            $sql = "INSERT INTO feature_request_table (username, desc, email, url, priority, status)
            VALUES( '$username' , '$desc' , '$email' , '$url' , '$priority' , '0' )";
            echo "The sql statement is: " . $sql . "</br>";
            mysql_query($sql);  
            //echo "The result is: " . $results . "</br>";  
            echo "Your request have been sent. Please allow a brief period of time for your webmaster implement your request. Thank you!";
        }


mysql_close($con);
?>
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  1. Editorial Team
    Editorial Team
    2026-05-23T07:01:45+00:00Added an answer on May 23, 2026 at 7:01 am

    Use the return value of mysql_query() and check if it is NULL to find out if the query was successful:

    $result = mysql_query($sql);
    
    // A NULL value of $result indicates failure
    if (!$result) {
      // something went wrong!
    
      // See the error...
      echo mysql_error();
    }
    

    Also, we don’t see in the posted code that mysql_connect() was called. Also check that the connection was successfully made:

    $conn = mysql_connect(all the connection details...);
    if (!$conn) {
      // connection failed
    }
    
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