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Home/ Questions/Q 6754883
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:20:03+00:00 2026-05-26T13:20:03+00:00

I’m feeling silly that I cannot figure this out, but it’s really starting to

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I’m feeling silly that I cannot figure this out, but it’s really starting to piss me off.

I’m simply trying to ensure the string contains only digits using string.match(regex). If it contains any non-numeric characters, hard code it to 9999999.

Here’s my code. I’m essentially checking to see if the results I pull from the ResultSet moduleResults contains no non-numeric characters before use it to setEndPointID which accepts a long as its parameter. The trim() is in there because there are often leading spaces in id_amr_module and I don’t want those to throw off the regex match. I’ve also tried the regex [0-9]* with no success.

String strEndPointID = moduleResults.getString("id_amr_module");
strEndPointID.trim();
if(strEndPointID.matches("\\d*")){
  msiRF.setEndpointID(moduleResults.getLong("id_amr_module"));
}
else{
  long lngEndPointID = 99999999;
  msiRF.setEndpointID(lngEndPointID);
}
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  1. Editorial Team
    Editorial Team
    2026-05-26T13:20:04+00:00Added an answer on May 26, 2026 at 1:20 pm

    You need start and end anchors to make sure the entire string is numeric. You also need to use + instead of * so that the regexp matches at least 1 digit (^\\d*$ would match the empty string). Fully refactored:

    long endPointID = 99999999;
    String strEndPointID = moduleResults.getString("id_amr_module").trim();
    if(strEndPointID.matches("^\\d+$")){
        endPointID = Long.parseLong(strEndPointID);
    }
    msiRF.setEndpointID(endPointID);
    
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